for the equation x^3+3x^2-4x-12 put in 3 then (in this order) put in 1,3,-4,-12 then put in either -3,-3,2 and your remainder will be zero. any other number will not have a remainder of zero.
4x^3−8x^2−12x+24 2,sqrt(3),-sqrt(3) x^3+3x^2-4x-12 -3,-2,2
