Fortunately the editor view doesn't lag The multiplying algorithm is has complexity of O(n^2) I might add multiplying by short constants (O(n) complexity) with there is need for performance. Might also check where are zeros to avoid unnecessary multiplications (and improve performance)
what is working: (Number1 < Number2) operator set Number1 to Number2 set Number1 to 0 Number1 + Number2 Number1 * Number2 Converting between high precision numbers and inputs (integers, rationals, 346232.23456e34) #library #all #trending #favourite #integer #addition #substraction #multiply #multiplication #guide #recent