C2A so, how does this base work? well, it starts out like bijective base 4, but then, once our first 10 (4) is reached, the bijective base switches from 4 to 8. once the next 10 (8) is reached (12 would be the number for it to trigger the next step), then the absorbable hundred is 6 after that, so 6 after 18 (12) is 100 (18). after that, we start over again from base 4. but then, after we reach the next 10 (8), we have the variable c. c stands for the counter of how many times have we passed another bij base 8's 10 (8). Right now, c = 0. c is also always 2b. b stands for the number it starts at. 6 + c = next order of magnitude, still bijective. then, it repeats: bij 4 > bij 8 > 10^n = 6. so, 18 would be 100, 38 would be 1000, etc. also, i'm hosting a competition on my yt: @TheBattleOfLuxuryCreator on YT.
C2A
