A simple simulation demonstrating probability. Instructions: 1. Click one of the doors 2. One of the incorrect doors that you did not choose will be removed 3. Click the blue to stay or the orange to switch to the other one available 4. If I made it correctly you should win more often by choosing orange due to probability. The chances that your first guess was correct is always 1/3. The chances that it was something else is 2/3. One door will be eliminated. It must not be the right door, and also cannot be the one you chose. There is a 2/3 chance that one of the two doors you didn't choose actually was correct, and a 2/3 chance that there is only one door available to be eliminated (since one is correct and one is chosen by you), and thus a 2/3 chance that the door that was not eliminated or chosen by you is correct. This entire situation hinges on the fact that the door you chose can't be revealed, which makes it kinda sneaky
I did it all, but mainly to explain to myself how this could possibly be true
