~~歡迎分享你的最佳紀錄~~ 遊玩方法：(以下以4位數為例) ① 先選擇你要3位數還是4位數的遊玩方式 ② 電腦會從0~9當中隨機選擇4個數字組成一組數， 接著要猜測答案，如果你選的數中有以下情況： →與答案其中一個數字相同，位置也相同，就會是A →與答案其中一個數字相同，但位置不同，則會是B ③ 透過各個結果中A和B的數量，推測電腦的答案 ④ 如果出現了4A，代表你猜中了答案，遊戲即結束 多多練習研究可以逐漸發現技巧喔 ou< ▪▫►▪▫►▪▫►▪▫►我是有點怪的分界線▪▫►▪▫►▪▫►▪▫► 原作者的話： 久違的遊戲 :D 這是我前天晚上突然想到的 ouo 因為我平時很喜歡玩1A2B，但有時候沒人能跟我一起玩，就乾脆直接做一個電腦版的 XD 整個專案編程+排版費時大約3~4hrs (刪了一些東西 DX 有 Bug 歡迎提出 uwu! (但不要是刻意製造的拉 w | ~~Welcome to share your best record~~ How to play: (The following takes 4 digits as an example) ① First choose whether you want a 3-digit or 4-digit play method ② The computer will randomly select 4 numbers from 0 to 9 to form a set of numbers. Then you have to guess the answer, if you choose any of the following: →It is the same as one of the numbers in the answer, and the position is also the same, it will be A →Same as one of the numbers in the answer, but in a different position, it will be B ③ According to the number of A and B in each result, infer the answer of the computer ④ If there is 4A, it means you guessed the answer correctly and the game is over A lot of practice and research can gradually discover skills OW< ▪▫►▪▫►▪▫►▪▫►I'm a little weird divider ▪▫►▪▫►▪▫►▪▫► Original author's words: Long-lost game :D This is what I suddenly thought of the night before owo Because I usually like to play 1A2B, but sometimes no one can play with me, so I just make a computer version XD The whole project programming + typesetting takes about 3~4hrs (deleted some things DX Bugs are welcome to submit uwu! (but don't pull it deliberately lol
