x = a*b (a and b is the closest pair of factors of x) a+b=c c = d*e (d and e is the closest pair of factors of c) ... 6 = 2 * 3 2 + 3 = 5 5 = 1 * 5 1+ 5 = 6 if it is a prime number, p = 1*p (p is a prime number) Given x > 5, prove that any number x will end in the 6,5 loop.
The NUMBERS list shows how the number progresses to 6 (or not). Bigger numbers may take more time Comment if you find any pattern in the conjecture!
